Q39. Which of the following alkyl halides will undergo SN2 reaction most readily?
(a) 1-Bromo-2,2-di

Q: What is the correct answer for CUET UG Chemistry Q39?

The correct answer is C. The rate of SN2 reactions is highly dependent on steric hindrance. Generally, reactivity order for SN2 is Methyl > Primary > Secondary > Tertiary, as less steric hindrance at the carbon bearing the leaving group allows for easier backside attack by the nucleophile.All options are primary alkyl bromides. We need to compare their steric hindrance.(a) 1-Bromo-2,2-dimethylpropane (neopentyl bromide):

Q: Q39. Which of the following alkyl halides will undergo SN2 reaction most readily? (a) 1-Bromo-2,2-dimethylpropane (b) 1-Bromo-2-methylbutane (c) 1-Bromobutane (d) 1-Bromo-3-methylbutane

The correct answer is C. The rate of SN2 reactions is highly dependent on steric hindrance. Generally, reactivity order for SN2 is Methyl > Primary > Secondary > Tertiary, as less steric hindrance at the carbon bearing the leaving group allows for easier backside attack by the nucleophile.All options are primary alkyl bromides. We need to compare their steric hindrance.(a) 1-Bromo-2,2-dimethylpropane (neopentyl bromide):

Q: What are the options for this CUET UG Chemistry question?

A. (a) 1-Bromo-2,2-dimethylpropane · B. (b) 1-Bromo-2-methylbutane · C. (c) 1-Bromobutane · D. (d) 1-Bromo-3-methylbutane

Question

Q39. Which of the following alkyl halides will undergo SN2 reaction most readily?
(a) 1-Bromo-2,2-dimethylpropane
(b) 1-Bromo-2-methylbutane
(c) 1-Bromobutane
(d) 1-Bromo-3-methylbutane

FirstInTest · Accepted Answer

The rate of SN2 reactions is highly dependent on steric hindrance. Generally, reactivity order for SN2 is Methyl > Primary > Secondary > Tertiary, as less steric hindrance at the carbon bearing the leaving group allows for easier backside attack by the nucleophile.All options are primary alkyl bromides. We need to compare their steric hindrance.(a) 1-Bromo-2,2-dimethylpropane (neopentyl bromide): (CH3)3CCH2Br. The carbon adjacent to the carbon with Br is tertiary, causing significant steric hindrance (bulky 'neopentyl' group).(b) 1-Bromo-2-methylbutane: CH3CH2CH(CH3)CH2Br. Steric hindrance is present at the carbon adjacent to the CH2Br group.(c) 1-Bromobutane: CH3CH2CH2CH2Br. This is a straight-chain primary alkyl halide, having the least steric hindrance.(d) 1-Bromo-3-methylbutane: (CH3)2CHCH2CH2Br. Steric hindrance is present further away from the CH2Br group than in (b).Comparing the primary halides, 1-bromobutane (c) has the least steric hindrance, making it the most reactive towards SN2 reaction.

Answer

(a) 1-Bromo-2,2-dimethylpropane

Answer

(b) 1-Bromo-2-methylbutane

Answer

(c) 1-Bromobutane

Answer

(d) 1-Bromo-3-methylbutane

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