Q16. What will be the time by light to travel 2 cm thickness of glass of refractive index 1.5?

Q: What is the correct answer for CUET UG Physics Q16?

The correct answer is d. To find the time taken by light to travel through the glass, we first need to determine the speed of light in the glass. The refractive index (μ) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v): μ = c/v. Therefore, v = c/μ. Given μ = 1.5 and c ≈ 3 × 10⁸ m/s, the speed of light in glass is v = (3 × 10⁸ m/s) / 1.5 = 2 × 10⁸ m/s. The thi

Q: Q16. What will be the time by light to travel 2 cm thickness of glass of refractive index 1.5?

The correct answer is d. To find the time taken by light to travel through the glass, we first need to determine the speed of light in the glass. The refractive index (μ) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v): μ = c/v. Therefore, v = c/μ. Given μ = 1.5 and c ≈ 3 × 10⁸ m/s, the speed of light in glass is v = (3 × 10⁸ m/s) / 1.5 = 2 × 10⁸ m/s. The thi

Q: What are the options for this CUET UG Physics question?

A. 2 x 10⁻¹⁰ s · B. 2.5 x 10⁻¹⁰ s · C. 2.25 x 10¹⁰ s · D. 10⁻¹⁰ s

Question

Q16. What will be the time by light to travel 2 cm thickness of glass of refractive index 1.5?

FirstInTest · Accepted Answer

To find the time taken by light to travel through the glass, we first need to determine the speed of light in the glass. The refractive index (μ) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v): μ = c/v. Therefore, v = c/μ. Given μ = 1.5 and c ≈ 3 × 10⁸ m/s, the speed of light in glass is v = (3 × 10⁸ m/s) / 1.5 = 2 × 10⁸ m/s. The thickness of the glass (distance) is d = 2 cm = 0.02 m. The time taken (t) is then given by t = d/v = (0.02 m) / (2 × 10⁸ m/s) = 0.01 × 10⁻⁸ s = 1 × 10⁻² × 10⁻⁸ s = 10⁻¹⁰ s. This matches option (d).

Answer

2 x 10⁻¹⁰ s

Answer

2.5 x 10⁻¹⁰ s

Answer

2.25 x 10¹⁰ s

Answer

10⁻¹⁰ s

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