The remainder when is divided by 19, is:

We need to find $(15^{23} + 23^{23}) \pmod{19}$. First, reduce the bases modulo 19: $15 \equiv -4 \pmod{19}$ $23 \equiv 4 \pmod{19}$ So, the expression becomes: $(-4)^{23} + (4)^{23} \pmod{19}$ Since 23 is an odd number, $(-4)^{23} = -(4^{23})$. Therefore, $-(4^{23}) + 4^{23} = 0$. So, the remainder is 0.

What is the correct answer for CUET UG Quantitative Aptitude?

The correct answer is D. We need to find $(15^{23} + 23^{23}) \pmod{19}$. First, reduce the bases modulo 19: $15 \equiv -4 \pmod{19}$ $23 \equiv 4 \pmod{19}$ So, the expression becomes: $(-4)^{23} + (4)^{23} \pmod{19}$ Since 23 is an odd number, $(-4)^{23} = -(4^{23})$. Therefore, $-(4^{23}) + 4^{23} = 0$. So, the remainder is 0.

The remainder when is divided by 19, is:

The correct answer is D. We need to find $(15^{23} + 23^{23}) \pmod{19}$. First, reduce the bases modulo 19: $15 \equiv -4 \pmod{19}$ $23 \equiv 4 \pmod{19}$ So, the expression becomes: $(-4)^{23} + (4)^{23} \pmod{19}$ Since 23 is an odd number, $(-4)^{23} = -(4^{23})$. Therefore, $-(4^{23}) + 4^{23} = 0$. So, the remainder is 0.