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If $y = \sin^{-1} x$ , then $(1 - x^2) \frac{d^2y}{dx^2}$ is equal to

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Q22. Match the blanks in List - I with suitable articles in List - II List-1 (A) Yesterday ______ European called at my office. (B) ______ sun shines bright. (C) Haven't you had ______ dinner yet? (D) I had ______ unexpected encounter. List - II (I) an (II) a (III) the (IV) No article Choose the correct answer from the options given below: (a) (A)-(IV), (B)-(III), (C)-(II), (D)-(1) (b) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (c) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (d) (A)-(II), (B)-(III), (C)-(IV), (D)-(1)

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If y=sin⁡−1x y = \sin^{-1} x y=sin−1x, then (1−x2)d2ydx2 (1 - x^2) \frac{d^2y}{dx^2} (1−x2)dx2d2y​ is equal to

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If y=sin⁡−1x y = \sin^{-1} x y=sin−1x, then (1−x2)d2ydx2 (1 - x^2) \frac{d^2y}{dx^2} (1−x2)dx2d2y​ is equal to

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If $y = \sin^{-1} x$ , then $(1 - x^2) \frac{d^2y}{dx^2}$ is equal to

If $y = \sin^{-1} x$ , then $(1 - x^2) \frac{d^2y}{dx^2}$ is equal to