Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass $= 500$g, Decay constant $= 20$ g/s then how much time is required for the amplitude of the system to drop to half of its initial value ? ($\ln 2 = 0.693$)

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(1) 34.65 s

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Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass $= 500$ g, Decay constant $= 20$ g/s then how much time is required for the amplitude of the system to drop to half of its initial value ? ( $\ln 2 = 0.693$ )

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Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass =500= 500=500g, Decay constant =20= 20=20 g/s then how much time is required for the amplitude of the system to drop to half of its initial value ? (ln⁡2=0.693\ln 2 = 0.693ln2=0.693)

Related questions

Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass $= 500$ g, Decay constant $= 20$ g/s then how much time is required for the amplitude of the system to drop to half of its initial value ? ( $\ln 2 = 0.693$ )