An electron of a hydrogen like atom, having $Z = 4$, jumps from $4^{th}$ energy state to $2^{nd}$ energy state. The energy released in this process, will be : (Given $Rch = 13.6eV$) Where R = Rydberg constant, c = Speed of light in vacuum, h = Planck's constant

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(1) $40.8eV$

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An electron of a hydrogen like atom, having $Z = 4$ , jumps from $4^{th}$ energy state to $2^{nd}$ energy state. The energy released in this process, will be : (Given $Rch = 13.6eV$ ) Where R = Rydberg constant, c = Speed of light in vacuum, h = Planck's constant

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An electron of a hydrogen like atom, having Z=4Z = 4Z=4, jumps from 4th4^{th}4th energy state to 2nd2^{nd}2nd energy state. The energy released in this process, will be : (Given Rch=13.6eVRch = 13.6eVRch=13.6eV) Where R = Rydberg constant, c = Speed of light in vacuum, h = Planck's constant

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An electron of a hydrogen like atom, having $Z = 4$ , jumps from $4^{th}$ energy state to $2^{nd}$ energy state. The energy released in this process, will be : (Given $Rch = 13.6eV$ ) Where R = Rydberg constant, c = Speed of light in vacuum, h = Planck's constant