In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g $\mathrm{mol^{-1}}$). Molar mass of barium sulphate is 233 g $\mathrm{mol^{-1}}$.

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Accepted Answer

21.97%

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In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g $\mathrm{mol^{-1}}$ ). Molar mass of barium sulphate is 233 g $\mathrm{mol^{-1}}$ .

Related questions

Questions

In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol−1\mathrm{mol^{-1}}mol−1). Molar mass of barium sulphate is 233 g mol−1\mathrm{mol^{-1}}mol−1.

Related questions

In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g $\mathrm{mol^{-1}}$ ). Molar mass of barium sulphate is 233 g $\mathrm{mol^{-1}}$ .