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Engineering

Let $f : \mathbb{R}\to\mathbb{R}$ be a polynomial function of degree four having extreme values at $x = 4$ and $x = 5$ . If $\lim_{x\to0} \frac{f(x)}{x^2} = 5$ , then $f(2)$ is equal to :

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A metal wire of uniform mass density having length L and mass M is bent to form a semicircular arc and a particle of mass m is placed at the centre of the arc. The gravitational force on the particle by the wire is: [Diagram: Semicircular arc with mass m at center]

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Questions

Let f:R→Rf : \mathbb{R}\to\mathbb{R}f:R→R be a polynomial function of degree four having extreme values at x=4x = 4x=4 and x=5x = 5x=5. If lim⁡x→0f(x)x2=5\lim_{x\to0} \frac{f(x)}{x^2} = 5limx→0​x2f(x)​=5, then f(2)f(2)f(2) is equal to :

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Questions

Let f:R→Rf : \mathbb{R}\to\mathbb{R}f:R→R be a polynomial function of degree four having extreme values at x=4x = 4x=4 and x=5x = 5x=5. If lim⁡x→0f(x)x2=5\lim_{x\to0} \frac{f(x)}{x^2} = 5limx→0​x2f(x)​=5, then f(2)f(2)f(2) is equal to :

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Let $f : \mathbb{R}\to\mathbb{R}$ be a polynomial function of degree four having extreme values at $x = 4$ and $x = 5$ . If $\lim_{x\to0} \frac{f(x)}{x^2} = 5$ , then $f(2)$ is equal to :

Let $f : \mathbb{R}\to\mathbb{R}$ be a polynomial function of degree four having extreme values at $x = 4$ and $x = 5$ . If $\lim_{x\to0} \frac{f(x)}{x^2} = 5$ , then $f(2)$ is equal to :