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Engineering

Let $f(x)$ be a positive function and $I_1 = \frac{1}{2} \int_{-1}^{2} 2xf(2x(1-2x)) dx$ and $I_2 = \int_{-1}^{2} f(x(1-x)) dx$ . Then the value of $\frac{I_2}{I_1}$ is equal to

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