When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is :
(Given molar mass in g mol$^{-1}$ H : 1, C : 12, N : 14, O : 16, S: 32)

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When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is :\n(Given molar mass in g mol $^{-1}$ H : 1, C : 12, N : 14, O : 16, S: 32)

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When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is :\n(Given molar mass in g mol−1^{-1}−1 H : 1, C : 12, N : 14, O : 16, S: 32)

Related questions

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is :\n(Given molar mass in g mol $^{-1}$ H : 1, C : 12, N : 14, O : 16, S: 32)