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$y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}(-4x^3 + 5x^2 + 1)^{1/2}\right)\right)$. Then, at $x = 1$, - FirstInTest | FirstInTest

Questions

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$y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}(-4x^3 + 5x^2 + 1)^{1/2}\right)\right)$ . Then, at $x = 1$ ,

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y=f(x)=sin⁡3(π3cos⁡(π32(−4x3+5x2+1)1/2))y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}(-4x^3 + 5x^2 + 1)^{1/2}\right)\right)y=f(x)=sin3(3π​cos(32​π​(−4x3+5x2+1)1/2)). Then, at x=1x = 1x=1,

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$y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}(-4x^3 + 5x^2 + 1)^{1/2}\right)\right)$ . Then, at $x = 1$ ,