Which of the following is an equivalent form of the equation of the graph shown in the xy-plane, fro

Q: What is the correct answer for SAT Maths?

The correct answer is D. The question asks for an equivalent form of the equation from which the vertex A can be identified as constants. This means we are looking for the vertex form of the quadratic equation, which is y = a(x - h)^2 + k, where (h, k) is the vertex. From the graph, the vertex A is at (1, -16). So, h = 1 and k = -16. The equation would be y = a(x - 1)^2 - 16. Let's check the original equation y = x^2 - 2x

Q: Which of the following is an equivalent form of the equation of the graph shown in the xy-plane, from which the coordinates of vertex A can be identified as constants in the equation? The graph shows…

The correct answer is D. The question asks for an equivalent form of the equation from which the vertex A can be identified as constants. This means we are looking for the vertex form of the quadratic equation, which is y = a(x - h)^2 + k, where (h, k) is the vertex. From the graph, the vertex A is at (1, -16). So, h = 1 and k = -16. The equation would be y = a(x - 1)^2 - 16. Let's check the original equation y = x^2 - 2x

Q: What are the options for this SAT Maths question?

A. y = (x + 3)(x - 5) · B. y = (x - 3)(x + 5) · C. y = x(x - 2) - 15 · D. y = (x - 1)^2 - 16

Question

Which of the following is an equivalent form of the equation of the graph shown in the xy-plane, from which the coordinates of vertex A can be identified as constants in the equation? The graph shows a parabola opening upwards, with the vertex A at (1, -16). The parabola crosses the x-axis at x = -3 and x = 5. The equation is y = x^2 - 2x - 15.

FirstInTest · Accepted Answer

The question asks for an equivalent form of the equation from which the vertex A can be identified as constants. This means we are looking for the vertex form of the quadratic equation, which is y = a(x - h)^2 + k, where (h, k) is the vertex.
From the graph, the vertex A is at (1, -16). So, h = 1 and k = -16. The equation would be y = a(x - 1)^2 - 16.
Let's check the original equation y = x^2 - 2x - 15. The coefficient of x^2 is 1, so a = 1.
Therefore, the vertex form is y = 1(x - 1)^2 - 16, or y = (x - 1)^2 - 16.
Let's verify this by expanding option D: (x - 1)^2 - 16 = (x^2 - 2x + 1) - 16 = x^2 - 2x - 15, which matches the given equation.
Options A and B are factored forms that show the x-intercepts (roots). Option C is a partial factorization.

Answer

y = (x + 3)(x - 5)

Answer

y = (x - 3)(x + 5)

Answer

y = x(x - 2) - 15

Answer

y = (x - 1)^2 - 16

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