Q.60. The correct statements among the following are :
A. Basic vanadium oxide is used in the manufa

Q: What is the correct answer for JEE Main Chemistry Q60?

The correct answer is C. Let's analyze each statement: A. Basic vanadium oxide is used in the manufacture of H$_2$SO$_4$. This is incorrect. Vanadium pentoxide (V$_2$O$_5$) is an acidic oxide and is used as a catalyst in the Contact Process for the manufacture of H$_2$SO$_4$. It is not basic. So, A is false. B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2

Q: Q.60. The correct statements among the following are : A. Basic vanadium oxide is used in the manufacture of HSO. B. The spin-only magnetic moment value of the transition metal halide employed in…

The correct answer is C. Let's analyze each statement: A. Basic vanadium oxide is used in the manufacture of H$_2$SO$_4$. This is incorrect. Vanadium pentoxide (V$_2$O$_5$) is an acidic oxide and is used as a catalyst in the Contact Process for the manufacture of H$_2$SO$_4$. It is not basic. So, A is false. B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2

Q: What are the options for this JEE Main Chemistry question?

A. A and B only · B. A, C and D only · C. C and D only · D. B and C and D only

Question

Q.60. The correct statements among the following are :
A. Basic vanadium oxide is used in the manufacture of HSO.
B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2.84 BM.
C. The p-block metal compound employed in Ziegler-Natta polymerization has the metal in +3 oxidation state.
D. The number of electrons present in the outer most 'd' orbital of metal halide employed in Wacker process is 8.
Choose the correct answer from the options given below:

FirstInTest · Accepted Answer

Let's analyze each statement:
A. Basic vanadium oxide is used in the manufacture of H$_2$SO$_4$. This is incorrect. Vanadium pentoxide (V$_2$O$_5$) is an acidic oxide and is used as a catalyst in the Contact Process for the manufacture of H$_2$SO$_4$. It is not basic. So, A is false.
B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2.84 BM. Ziegler-Natta catalyst typically involves TiCl$_4$ and Al(C$_2$H$_5$)$_3$. In TiCl$_4$, Ti is in the +4 oxidation state (d$^0$ configuration), so it has 0 unpaired electrons and a magnetic moment of 0 BM. Sometimes TiCl$_3$ is used, where Ti is +3 (d$^1$), with 1 unpaired electron, giving a magnetic moment of $\sqrt{1(1+2)} = \sqrt{3} \approx 1.73$ BM. If it's a different transition metal, say VCl$_3$ (V is +3, d$^2$), it would have 2 unpaired electrons, giving $\sqrt{2(2+2)} = \sqrt{8} \approx 2.83$ BM. So, if the transition metal is V(III), this statement could be true. Given the options, it's likely referring to VCl$_3$ or a similar compound. Let's keep this as potentially true.
C. The p-block metal compound employed in Ziegler-Natta polymerization has the metal in +3 oxidation state. The p-block metal compound is typically an alkyl aluminum compound, like triethylaluminium (Al(C$_2$H$_5$)$_3$). In this compound, Aluminum (Al) is a p-block element, and its oxidation state is +3. So, C is true.
D. The number of electrons present in the outer most 'd' orbital of metal halide employed in Wacker process is 8. The Wacker process uses PdCl$_2$ as a catalyst. In PdCl$_2$, Palladium (Pd) is in the +2 oxidation state. The electronic configuration of Pd is $[Kr] 4d^{10} 5s^0$. So, Pd$^{2+}$ is $[Kr] 4d^8$. Thus, there are 8 electrons in the outermost 'd' orbital. So, D is true.

Now let's re-evaluate B. If VCl$_3$ is used, then B is true. If TiCl$_3$ is used, then B is false. Given that C and D are definitely true, let's check the options. Option (3) is C and D only. This means B is considered false. If B is false, it implies that the transition metal halide used in Ziegler-Natta polymerization does not have a magnetic moment of 2.84 BM. This is consistent if TiCl$_4$ (d$^0$) or TiCl$_3$ (d$^1$) is considered the primary component. So, A is false, B is false, C is true, D is true. Therefore, C and D are the correct statements.

Answer

A and B only

Answer

A, C and D only

Answer

C and D only

Answer

B and C and D only

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